Matematik SPM Sebenar 2025, Kertas 2 (Soalan 1 – 3)
Soalan 1:(a) Tukarkan 15026 kepada nombor dalam asas sepuluh. [2 markah](b) Diberi bahawa 51079 – X9 = 3489.Cari nilai X. [2 markah]Penyelesaian:(a)$$ \begin{aligned} & 1\left(6^3\right)+5\left(6^2\right)+0\left(6^1\right)+2\left(6^0\right) \\ & =216+180+0+2 \\ & =398 \end{aligned} $$(b)$$ \begin{aligned} & 5107_9-348_9 \\ & =\left[5\left(9^3\right)+1\left(9^2\right)+0\left(9^1\right)+7\left(9^0\right)\right]-\left[3\left(9^2\right)+4\left(9^1\right)+8\left(9^0\right)\right] \\ & =3733_{10}-287_{10} \\ & =3446_{10} \end{aligned} $$X = 4648 Soalan 2:Jadual 1 menunjukkan nilai-nilai bagi … Read more